(y+1)(3y^2+5y-2)=

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Solution for (y+1)(3y^2+5y-2)= equation: 


Simplifying
(y + 1)(3y2 + 5y + -2) = 0

Reorder the terms:
(1 + y)(3y2 + 5y + -2) = 0

Reorder the terms:
(1 + y)(-2 + 5y + 3y2) = 0

Multiply (1 + y) * (-2 + 5y + 3y2)
(1(-2 + 5y + 3y2) + y(-2 + 5y + 3y2)) = 0
((-2 * 1 + 5y * 1 + 3y2 * 1) + y(-2 + 5y + 3y2)) = 0
((-2 + 5y + 3y2) + y(-2 + 5y + 3y2)) = 0
(-2 + 5y + 3y2 + (-2 * y + 5y * y + 3y2 * y)) = 0
(-2 + 5y + 3y2 + (-2y + 5y2 + 3y3)) = 0

Reorder the terms:
(-2 + 5y + -2y + 3y2 + 5y2 + 3y3) = 0

Combine like terms: 5y + -2y = 3y
(-2 + 3y + 3y2 + 5y2 + 3y3) = 0

Combine like terms: 3y2 + 5y2 = 8y2
(-2 + 3y + 8y2 + 3y3) = 0

Solving
-2 + 3y + 8y2 + 3y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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